Systems of linear equations: An equation of a line
The equation of a line
We have seen that solutions of the form #\blue p \cdot x + \green q\cdot y+\purple r=0# have a line as solutions. We have also seen that the linear formula #y = a\cdot x+b# has a line as a graph. Hence, there are two ways of describing the equation of a line.
#y=-{{6\cdot x}\over{7}}#
Because the coefficient of #y# is not equal to zero in the given equation, it is possible to reduce the equation to the form #y=a\cdot x+b#. We achieve this form through reduction:
\[\begin{array}{rcl}
-6\cdot x-7\cdot y&=&0 \\&&\phantom{xxx}\blue{\text{the given equation}}\\
-7\cdot y&=&6\cdot x \\&&\phantom{xxx}\blue{\text{added }6\cdot x\text{ left and right}}\\
y&=&\displaystyle -{{6\cdot x}\over{7}}\\&&\phantom{xxx}\blue{\text{left and right divided by the coefficient of }y}
\end{array}\]
Because the coefficient of #y# is not equal to zero in the given equation, it is possible to reduce the equation to the form #y=a\cdot x+b#. We achieve this form through reduction:
\[\begin{array}{rcl}
-6\cdot x-7\cdot y&=&0 \\&&\phantom{xxx}\blue{\text{the given equation}}\\
-7\cdot y&=&6\cdot x \\&&\phantom{xxx}\blue{\text{added }6\cdot x\text{ left and right}}\\
y&=&\displaystyle -{{6\cdot x}\over{7}}\\&&\phantom{xxx}\blue{\text{left and right divided by the coefficient of }y}
\end{array}\]
Unlock full access
Teacher access
Request a demo account. We will help you get started with our digital learning environment.
Student access
Is your university not a partner?
Get access to our courses via Pass Your Math independent of your university. See pricing and more.
Or visit omptest.org if jou are taking an OMPT exam.
Or visit omptest.org if jou are taking an OMPT exam.