Trigonometry: Angles with sine, cosine and tangent
Symmetry in the unit circle
If you know the values of the cosine and sine of the special angles between #0# and #\frac{\pi}{2}#, then you can calculate the values of special angles between #\frac{\pi}{2}# and #2 \pi# by using mirror symmetry.
Given is #\sin\left(\frac{\pi}{4}\right)=\dfrac{1}{\sqrt{2}}#. What is #\sin\left(\frac{5 \pi}{4}\right)#?
Given is #\sin\left(\frac{\pi}{4}\right)=\dfrac{1}{\sqrt{2}}#. What is #\sin\left(\frac{5 \pi}{4}\right)#?
#\sin\left(\frac{5 \pi}{4}\right)=# |
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